x^2*3.14=16

Solution for x^2*3.14=16 equation:

x^2*3.14=16

We move all terms to the left:

x^2*3.14-(16)=0

Wy multiply elements

3.14x^2-16=0

a = 3.14; b = 0; c = -16;
Δ = b2-4ac
Δ = 02-4·3.14·(-16)
Δ = 200.96
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-\sqrt{200.96}}{2*3.14}=\frac{0-\sqrt{200.96}}{6.28}
=-\frac{\sqrt{}}{6.28}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+\sqrt{200.96}}{2*3.14}=\frac{0+\sqrt{200.96}}{6.28}
=\frac{\sqrt{}}{6.28}
$